Diana - Pine #74
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Diana - Pine #74
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kyra-patton
reviewed
Jul 28, 2022
| def __init__(self, value, next_node = None, prev_node = None): | ||
| self.value = value | ||
| self.next = next_node | ||
| self.previous = prev_node #This line because this is a doubly linked list |
| # Space Complexity: ? | ||
| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def get_first(self): |
| # Space Complexity: ? | ||
| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def add_first(self, value): |
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def search(self, value): |
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def length(self): |
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max(self): |
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def delete(self, value): |
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| if new.value == value: | ||
| break |
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We generally try and avoid using break statements unless really necessary. Might you be able to refactor your code to eliminate this?
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) |
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🪐 Space complexity will be O(n) here because the function creates a helper_list which will end up holding all the nodes in the linked list
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def reverse(self): |
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Since you have a doubly linked list you also need to think about how you redirect your previous and tail pointers.
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